ajax php 实现写入数据库_PHP教程

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首先需要一个带输入表格.


复制代码 代码如下:

Insert 知识点

知识点

答案

需要js来处理提交数据到服务器上以及从服务器获取提交后的返回数据. submit.js代码如:


复制代码 代码如下:

/*

* To change this template, choose Tools | Templates

* and open the template in the editor.

*/

var xmlHttp;

function getValue(){

alert("getvaluel");

var question =document.insertForm.question.value;

// alert(question);

var answer = document.insertForm.answer.value;

// alert(answer);

submit(question,answer);

};

function submit(question,answer){

xmlHttp=GetXmlHttpObject();

if (xmlHttp==null)

{

alert ("Your browser does not support AJAX!");

return;

}

xmlHttp.onreadystatechange =function(){

if(xmlHttp.readyState ==4){

alert(xmlHttp.responseText);

}

};

var url = "insert1.php";

xmlHttp.open("post",url,true);

xmlHttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded; charset=utf-8");

xmlHttp.send("question="+question+"&answer="+answer);

}

function GetXmlHttpObject()

{

var xmlHttp=null;

try

{

// Firefox, Opera 8.0+, Safari

xmlHttp=new XMLHttpRequest();

}

catch (e)

{

// Internet Explorer

try

{

xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");

}

catch (e)

{

xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");

}

}

return xmlHttp;

}

然后PHP处理界面,负责跟服务器交换数据


复制代码 代码如下:

/*

* To change this template, choose Tools | Templates

* and open the template in the editor.

*/

//echo $_POST["question"];

//echo $_POST["answer"];

$q =$_POST['question'];

$a = $_POST['answer'];

//$q='qq';

//$a="a";

$con = mysql_connect("localhost","joe","123");

if (!$con)

{

//die('Could not connect: ' . mysql_error());

echo 'Could not connect: ' . mysql_error();

}

mysql_select_db("joe",$con);

mysql_query("INSERT INTO message VALUES ('$q', '$a', '无')");

mysql_close($con);

echo "输入成功";

?>

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  • 本文由 发表于 2020年8月21日 13:33:46
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